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1) Initial settings. (what we have before construction)

2) the Desired result (the one that we want to get)

3) Calculation (we consider the air, fuel, power etc.)

4) Selection of the components (turbine, parts, etc.)

5) Installation (actually Assembly)

6) setup (ECU, pressure, fuel, etc.)

That's it for this scheme will work.

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Size: 2.4 L (2378 QC)

Cylinder: 87 mm

Stroke: 100 mm

Power: 160 HP. (117 kW) at 5750 rpm. with 158 ft·lbf (215 N·m) at 4000 rpm.

Compression ratio : 9,5

MFI fuel injection,

4 valves per cylinder.

Valves without the hydro-compensators.

Automatic gearbox F4A4B.

For the beginning of these parameters are sufficient.

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Oh, this item is always causes a lot of disputes. the voices of the people hundreds of horsepower. But not all people understand that they can use them. You can build any engine. And 400, and 500, and 1000 HP, etc.

However, any increase shall entail significant spending. This relates primarily to the engine itself. Need to strengthen the pistons, rods, gear box, transmission, etc. The total amount of construction is increasing to infinity. Therefore, we must descend from the heavens to the earth and calculate what you can do.

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What hp is a gt 6 speed rated up too handle ?

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If the duty cycle is equal to 90%, fuel rail pressure of 3 bar.

The power can be calculated as: the Size of the injector : 5.25 x number of cylinders.

Stock size GS injector = 275 cc.

275 : 5.25 x 4 = 209.5

Thus, the stock injectors, will be able to secure the capacity of 210 HP.

That is, if you take the injectors for example from GT = 305cc. 305 : 5.25 x 4 = 232 HP.

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Now you need to make the calculation of the air.

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Basic air flow = V x rpm x 0.5 x E / 1000000

where, V - volume (cc), rpm - (6000) 0.5 - of 0.5 means that the four-stroke engine air in the cylinder comes only at the time of one turnover of the two. E - filling ratio (0.85). The number of 1000000 serves to convert cc to cubic meters.

2378 x 6000 x 0.5 x 0.85 /1000000 = 6.06 m3/min

This is a basic air flow N/A engine. Remember this number.

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Rated power = the initial power x (the boost pressure /atmospheric pressure)

Make an equation.

210 = 160 x ( X / 1 bar)

210 = 160 x X

X = 210 / 160

X = 1.31bar (absolute pressure = atmospheric pressure + boost pressure

For achievement of the power 210 hp need to 0.31 bar (4.5 psi) boost pressure

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air flow turbo = boost pressure x basic air flow

1.31 x 6.06 = 7.94 m3/min

To convert m3/min to a more correct term kg/min, m3/min should be multiplied by the density of the air at a height of geographic location (sorry, inscriptions in Russian)

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7.94 / 60 = 0.13 kg per second

Now I take the directory and find the desired me turbocharger

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the total compression ratio = compression ratio + (boost pressure) in square

9.5 + (0.31x0.31) = 9.6

As you can see, nothing will not need to change.

if you calculates high boost pressure, for example 1.5 bar (21psi)

9.5 + (1.5x1.5) = 11.75

in this case it is necessary to reduce the CR.

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Thank you, I would be very grateful!Please, everyone, e-rep this guy!

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